Single Choice

Which one of the following does not have a pyramidal shape?

A$$(CH_3)_3 N$$
B$$P(CH_3)_3$$
C$$P(SiH_3)_3$$
D$$(SiH_3)_3 N$$
Correct Answer

Solution

$$N(SiH_3)_3$$ has a planar geometry due to back bonding between empty 3d orbital of Si and filled 2p orbital of N. $$(CH_3)_3N, (SiH_3)_3P$$ and $$(CH_3)_3P$$ have pyramidal geometry due to absence of back bonding. Nitrogen and Phosphorus are $$sp^3$$ hybridized out of which 3 hybrid orbitals are used for bond making and 1 lone pair is present in fourth orbital.

SIMILAR QUESTIONS

Chemical Bonding

$$BF_{3}$$ forms an adduct with $$NH_{3}$$ because:

Chemical Bonding

PF$$_{3}$$ can act as a donor molecule while NF$$_{3}$$ shows little tendency to act as a donor. This is because in PF$$_{3}$$, lone-pair on P is easily donated compared to that of N.

Chemical Bonding

Which of the following can act as Lewis acid?

Chemical Bonding

Which of the following molecule is not hypovalent

Chemical Bonding

Which of the following does not contain any coordinate bond?

Chemical Bonding

Which of the following does not contain any coordinate bond?

Chemical Bonding

Explain the following on the basis of valence bond theory: $$BF_{3}$$ is planar but $$NH_{3}$$ is not.

Chemical Bonding

$$BF_3$$ has less lewis acidic property than $$BBr_3$$ . Why ?

Chemical Bonding

$$(CH_3)_3$$ COH is less acid than $$(CH_3)_3$$ SiOH. Why ?

Chemical Bonding

In co-ordinate bonds, the acceptor atoms must essentially contain in its valency shell an orbitial:

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