Chemical Bonding
$$BF_{3}$$ forms an adduct with $$NH_{3}$$ because:
Which of the following can act as Lewis acid?
Lewis Acid: A species that accepts an electron pair (i.e., an electrophile) and will have vacant orbitals.
Lewis acids accept an electron pair. Lewis Acids are electrophilic meaning that they are electron attracting. When bonding with a base the acid uses its lowest unoccupied molecular orbital
Various species can act as Lewis acids. All cations are Lewis acids since they are able to accept electrons. (e.g., $$Cu^{2+}, Fe^{2+}, Fe^{3+}$$)
An atom, ion, or molecule with an incomplete octet of electrons can act as an Lewis acid (e.g., $$BF_3, AlF_3$$).
Molecules where the central atom can have more than 8 valence shell electrons can be electron acceptors due to the presence of empty d-orbitals, and thus, are classified as Lewis acids (e.g., $$SiBr_4, SiF_4, SnCl_4, SF_4$$).
Molecules that have multiple bonds between two atoms of different electronegativities (e.g., $$CO_2, SO_2$$)
But in $$CCl_4$$ there is no vacant d-orbitals available for carbon.
Hence options A,B & D are correct.
$$BF_{3}$$ forms an adduct with $$NH_{3}$$ because:
PF$$_{3}$$ can act as a donor molecule while NF$$_{3}$$ shows little tendency to act as a donor. This is because in PF$$_{3}$$, lone-pair on P is easily donated compared to that of N.
Which of the following molecule is not hypovalent
Which of the following does not contain any coordinate bond?
Which one of the following does not have a pyramidal shape?
Which of the following does not contain any coordinate bond?
Explain the following on the basis of valence bond theory: $$BF_{3}$$ is planar but $$NH_{3}$$ is not.
$$BF_3$$ has less lewis acidic property than $$BBr_3$$ . Why ?
$$(CH_3)_3$$ COH is less acid than $$(CH_3)_3$$ SiOH. Why ?
In co-ordinate bonds, the acceptor atoms must essentially contain in its valency shell an orbitial: