Single Choice

Polarisation of electrons in acrolein may be written as :

A$$\overset { -\delta }{ C } { H }_{ 2 }=CH-\overset { +\delta }{ C } =O$$
B$$\overset { -\delta }{ C } { H }_{ 2 }=CH-CH=\overset { +\delta }{ O }$$
C$$\overset { -\delta }{ C } { H }_{ 2 }=\overset { +\delta }{ C } H-CH=O$$
D$$\overset { +\delta }{ C } { H }_{ 2 }=CH-CH=\overset { -\delta }{ O }$$
Correct Answer

Solution

Polarisation of electrons in acrolein may be written as $$\overset { +\delta }{ C } { H }_{ 2 }=CH-CH=\overset { -\delta }{ O }$$.
O atom is more EN than C atom, so it acquires $$\left(-\delta\right)$$ charge and C atom acquires $$\left(+\delta\right)$$ charge which is transferred to the last C atom.

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